I'm having some problems with my Algebra 2 Word Problems. Help?
So, it's about 1:30 AM and i've been up half the night working on this work. I've googled how to work these problems and nothing has helped so far. Hopefully i'll have more luck on here. lol Alright, here's the question. In 1998 an airline offered a special airfare of $201 to fly from Cincinnati to Washington, D.C., a distance of about 386 miles. Special airfares offered for longer flights increased by about $.138 per mile. Write a linear model for the special airfares (a) based on the total number of miles (t) of the flight. Estimate the airfare offered for a flight from Boston to Sacramento, a distance of 2629 miles.
Mathematics - 3 Answers
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1 :
a = 201 + 0.138(t - 386) a = 201 + 0.138(2629 - 386) = 510.534 or $510.53
2 :
2629 - 386 = 2243 2 243 * .138 = 309.53400 309.53400+201=510.53400 Answer: $510.53
3 :
1st way of looking at the problem: Special airfare for longer flights (d = distance): = d($201.00/386 + $0.138) = d($0.520725 + $0.138) = $0.658725d Answer (a): cost for longer flights = $0.658725d ---------------- = $0.658725(2,629) = $1,731.79 Answer (b): $1,731.79 ------------------------------------------------------------------------------ ------------------------------------------------------------------------------ 2nd way of looking at the problem: = $201.00 + ([d - 386])[$201/386 + $0.138]) = $201.00 + ([d - 386][$0.520725389 + 0.138]) = $201.00 + ($0.658725389[d - 386]) = $201.00 + $0.658725389d - $254.268 = $0.658725389d - $53.268 Answer (a): special airfare for all flights = $0.658725389d - $53.268 ---------------- Using the formula above on both flights: Cincinnati to Washington, D.C. & Boston to Sacramento: Airfare from Boston to Sacramento: = $0.658725389(2,629 mi) - $53.268 = $1,645.032 - $53.268 = $1,678.52 Airfare from Cincinnati to Washington, D.C.: = $0.658725389(386 miles) - $53.268 = $254.268 - $53.268 = $201.00 Answer: Boston to Sacramento, $1,678.52; Cincinnati to Washington, D.C. is the usual $201.00.
